lua split by backslash

snalbansed · Jan 12th 2017

Dear all, particularly Lua fans!

I need to extract the A or B from

Code

0008,0008  Image Type: DERIVED\PRIMARY\SINGLE PLANE\SINGLE A 
or
0008,0008  Image Type: DERIVED\PRIMARY\SINGLE PLANE\SINGLE B\STORE FLUORO

I've been trying to work out how to do it with string.gmatch, some character escaping and regex, but both my Lua and my regex are too weak to get anything to work.

Will anyone take pity on me?

Your's hopefully...

Ed

P.S. if there is a function to call Data.ImageType[4] or equivalent that would be awesome too...

marcelvanherk · Jan 13th 2017

Hi,

I typically use something like string.split:

Code

function string.split(str, pat)
   local t = {} 
   local fpat = "(.-)" .. pat
   local last_end = 1
   local s, e, cap = str:find(fpat, 1)
   while s do
      if s ~= 1 or cap ~= "" then
	 table.insert(t,cap)
      end
      last_end = e+1
      s, e, cap = str:find(fpat, last_end)
   end
   if last_end <= #str then
      cap = str:sub(last_end)
      table.insert(t, cap)
   end
   return t
end

Display More

This would be used as follows:

types = string.split(Data.ImageType, '\\')
types[4] is what you want

Marcel

snalbansed · Jan 13th 2017

Thanks. I'll give it a go.

snalbansed · Jan 16th 2017

That worked, and I'll keep it in reserve for the next time I need such a thing, but in the end I was over-complicating it!

Code

if string.find(Data.ImageType, 'SINGLE A') then

was sufficient for this purpose.

Thanks again.

lua split by backslash

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